6d5f4c418a
There are a few places where tests repeatedly concatenate strings to
themselves in order to make them very long. Using `.repeat()` makes the
code clearer.
For example, before:
for (var i = 0; i < 8; ++i) lots_of_headers += lots_of_headers;
After:
lots_of_headers = lots_of_headers.repeat(256);
Using `.repeat()` makes it clear that the string will be repeated 256
times rather than 8 times. ("What?! That first one doesn't repeat 256
times! It only repeats 8... Oh, wait. Yes, I see your point now.")
PR-URL: https://github.com/nodejs/node/pull/5311
Reviewed-By: James M Snell <jasnell@gmail.com>
Reviewed-By: Michaël Zasso <mic.besace@gmail.com>
Reviewed-By: Sakthipriyan Vairamani <thechargingvolcano@gmail.com>
46 lines
1.3 KiB
JavaScript
46 lines
1.3 KiB
JavaScript
'use strict';
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// This is the same as test/simple/test-crypto, but from before the shift
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// to use buffers by default.
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var common = require('../common');
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var assert = require('assert');
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if (!common.hasCrypto) {
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console.log('1..0 # Skipped: missing crypto');
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return;
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}
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var crypto = require('crypto');
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var EXTERN_APEX = 0xFBEE9;
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// manually controlled string for checking binary output
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var ucs2_control = 'a\u0000';
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// grow the strings to proper length
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while (ucs2_control.length <= EXTERN_APEX) {
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ucs2_control = ucs2_control.repeat(2);
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}
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// check resultant buffer and output string
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var b = new Buffer(ucs2_control + ucs2_control, 'ucs2');
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//
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// Test updating from birant data
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//
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(function() {
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var datum1 = b.slice(700000);
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var hash1_converted = crypto.createHash('sha1')
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.update(datum1.toString('base64'), 'base64')
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.digest('hex');
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var hash1_direct = crypto.createHash('sha1').update(datum1).digest('hex');
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assert.equal(hash1_direct, hash1_converted, 'should hash the same.');
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var datum2 = b;
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var hash2_converted = crypto.createHash('sha1')
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.update(datum2.toString('base64'), 'base64')
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.digest('hex');
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var hash2_direct = crypto.createHash('sha1').update(datum2).digest('hex');
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assert.equal(hash2_direct, hash2_converted, 'should hash the same.');
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})();
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